How to find number of trailing 0s in a binary number?Based on K&R bitcount example of finding 1s in a binary number i modified it a bit to find the trailing 0s.
int bitcount(unsigned x)
{
int b;
for(b=0;x!=0;x>>=1)
{
if(x&01)
break;
else
b++;
}
I would like to review this method.
Given an integer, count the number of trailing zeroes. For example, for n = 12, its binary representation is 1100 and number of trailing zero bits is 2. Examples : Input : 8 Output : 3 Binary of 8 is 1000, so there are three trailing zero bits.
To determine the number of significant figures in a number use the following 3 rules: Non-zero digits are always significant. Any zeros between two significant digits are significant. A final zero or trailing zeros in the decimal portion ONLY are significant.
You can get the number of zeros by subtracting ones(num) from the total number of digits.
Here's a way to compute the count in parallel for better efficiency:
unsigned int v; // 32-bit word input to count zero bits on right
unsigned int c = 32; // c will be the number of zero bits on the right
v &= -signed(v);
if (v) c--;
if (v & 0x0000FFFF) c -= 16;
if (v & 0x00FF00FF) c -= 8;
if (v & 0x0F0F0F0F) c -= 4;
if (v & 0x33333333) c -= 2;
if (v & 0x55555555) c -= 1;
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