Find unique list of tuples irrespective of order inside tuple

Question

Given input:

[('is','my','order'), ('my','order', 'is'), ('temp', 'ques'), ('ques','temp')]

Desired output:

[('is','my','order'), ('temp', 'ques')]

In the output, the order of the tuple or the order of the contents of tuple doesn't matter.

Answer 1

Because for you order doesn't matter, you can use set to achieve this:

>>> input_list = [('is','my','order'), ('my','order', 'is'), ('temp', 'ques'), ('ques','temp')]

>>> set(tuple(sorted(l)) for l in input_list)
set([('ques', 'temp'), ('is', 'my', 'order')])

Firstly sort the content of each nested tuple to ensure your set considers tuples with common items as same. Then I am type-casting it again to tuple because sorted returns list which are unhashable. Finally, set removes duplicate entries of your tuples.

Please refer "set" documentation for more details.