I made a little recursive algorithm to find a solution to a maze in the following format
###S###
##___##
##_#_##
#__#_##
#E___##
Where a '#' represents a wall, and '_' represents an open space (free to move through). 'S' represents the start location, 'E' represents the end location.
My algorithm works fine, but I'm wondering how to modify it to work for the shortest path.
/**
* findPath()
*
* @param location - Point to search
* @return true when maze solution is found, false otherwise
*/
private boolean findPath(Point location) {
// We have reached the end point, and solved the maze
if (location.equals(maze.getEndCoords())) {
System.out.println("Found path length: " + pathLength);
maze.setMazeArray(mazeArray);
return true;
}
ArrayList<Point> possibleMoves = new ArrayList<Point>();
// Move Right
possibleMoves.add(new Point(location.x + 1, location.y));
// Down Move
possibleMoves.add(new Point(location.x, location.y - 1));
// Move Left
possibleMoves.add(new Point(location.x - 1, location.y));
// Move Up
possibleMoves.add(new Point(location.x, location.y + 1));
for (Point potentialMove : possibleMoves) {
if (spaceIsFree(potentialMove)) {
// Move to the free space
mazeArray[potentialMove.x][potentialMove.y] = currentPathChar;
// Increment path characters as alphabet
if (currentPathChar == 'z')
currentPathChar = 'a';
else
currentPathChar++;
// Increment path length
pathLength++;
// Find the next path to traverse
if (findPath(potentialMove)) {
return true;
}
// Backtrack, this route doesn't lead to the end
mazeArray[potentialMove.x][potentialMove.y] = Maze.SPACE_CHAR;
if (currentPathChar == 'a')
currentPathChar = 'z';
else
currentPathChar--;
// Decrease path length
pathLength--;
}
}
// Previous space needs to make another move
// We will also return false if the maze cannot be solved.
return false;
}
In the first block is where I find the path and break it out. The char[][] array with the path written on it is set as well, which is later printed out as the result.
It works well, but I'm wondering what would be the best way to modify it to not break out after it finds the first successful path, but keep going until it finds the shortest possible path.
I tried doing something like this, modifying the findPath() method and adding a shortestPath and hasFoundPath variable. The first indicating length of the shortest path found so far, and the hasFoundPath variable indicating whether or not we have found any path.
// We have reached the end point, and solved the maze
if (location.equals(maze.getEndCoords())) {
System.out.println("Found path length: " + pathLength);
// Is this path shorter than the previous?
if (hasFoundPath && pathLength < shortestPathLength) {
maze.setMazeArray(mazeArray);
shortestPathLength = pathLength;
} else if (!hasFoundPath) {
hasFoundPath = true;
maze.setMazeArray(mazeArray);
shortestPathLength = pathLength;
}
//return true;
}
But I haven't been able to get it to set the mazeArray to the correct values of any shortest path it may find.
Any guidance would be appreciated :) Thanks
spaceIsFree() method simply makes sure the up/left/down/right coordinates are valid before moving to them. So it makes sure the char is an '_' or 'E' and it isn't out of bounds.
Dijkstra's Algorithm is one of the more popular basic graph theory algorithms. It is used to find the shortest path between nodes on a directed graph.
Trémaux's algorithm, invented by Charles Pierre Trémaux, is an efficient method to find the way out of a maze that requires drawing lines on the floor to mark a path, and is guaranteed to work for all mazes that have well-defined passages, but it is not guaranteed to find the shortest route.
Given an n x n binary matrix grid , return the length of the shortest clear path in the matrix. If there is no clear path, return -1 . A clear path in a binary matrix is a path from the top-left cell (i.e., (0, 0) ) to the bottom-right cell (i.e., (n - 1, n - 1) ) such that: All the visited cells of the path are 0 .
Your code appears to perform a depth-first search (DFS). To find the shortest path you will want to switch to a breadth-first search (BFS). It's not something you can do by adding a few variables to your existing code. It will require rewriting your algorithm.
One way to convert a DFS into a BFS is to get rid of the recursion and switch to using an explicit stack to keep track of which nodes you've visited so far. Each iteration of your search loop, you (1) pop a node off the stack; (2) check if that node is the solution; and (3) push each of its children onto the stack. In pseudo code, that looks like:
Depth-first search
stack.push(startNode)
while not stack.isEmpty:
node = stack.pop()
if node is solution:
return
else:
stack.pushAll(node.children)
If you then switch the stack to a queue this will implicitly become a BFS, and a BFS will naturally find the shortest path(s).
Breadth-first serarch
queue.add(startNode)
while not queue.isEmpty:
node = queue.remove()
if node is solution:
return
else:
queue.addAll(node.children)
A couple of additional notes:
The above algorithms are suitable for trees: mazes that don't have loops. If your mazes have loops then you'll need to make sure you don't revisit nodes you've already seen. In that case, you'll need to add logic to keep track of all the already visited nodes and avoid adding them onto the stack/queue a second time.
As written, these algorithms will find the target node but they don't remember the path that got them there. Adding that is an exercise for the reader.
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