I use a command to recursively find files containing a certain string1
:
find . -type f -exec grep -H string1 {} \;
I need to find files containing multiple strings, so the command should return those containing all strings. Something like this:
find . -type f -exec grep -H string1 AND string2 {} \;
I couldn't find a way. The strings can be anywhere in the files. Even a solution for only two strings would be nice.
you can also try this;
find . -type f -exec grep -l 'string1' {} \; | xargs grep -l 'string2'
this shows file names that contain string1 and string2
You can chain your actions and use the exit status of the first one to only execute the second one if the first one was successful. (Omitting the operator between primaries defaults to -and
/-a
.)
find . -type f -exec grep -q 'string1' {} \; -exec grep -H 'string2' {} \;
The first grep command uses -q
, "quiet", which returns a successful exit status if the string was found.
To collect all files containing string1
and then run the search for string2
with just a single invocation of grep, you could use -exec ... {} +
:
find . -type f -exec grep -q 'string1' {} \; -exec grep 'string2' {} +
with GNU grep
grep -rlZ 'string1' | xargs -0 grep -l 'string2'
from man grep
-r, --recursive
Read all files under each directory, recursively, following symbolic links only if they are on the command line. Note that if no file operand is given, grep searches the working directory. This is equivalent to the -d recurse option.
-Z, --null Output a zero byte (the ASCII NUL character) instead of the character that normally follows a file name. For example, grep -lZ outputs a zero byte after each file name instead of the usual newline. This option makes the output unambiguous, even in the presence of file names containing unusual characters like newlines. This option can be used with commands like find -print0, perl -0, sort -z, and xargs -0 to process arbitrary file names, even those that contain newline characters.
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