I want to pull out duplicate records in a MySQL Database. This can be done with:
SELECT address, count(id) as cnt FROM list GROUP BY address HAVING cnt > 1
Which results in:
100 MAIN ST 2
I would like to pull it so that it shows each row that is a duplicate. Something like:
JIM JONES 100 MAIN ST JOHN SMITH 100 MAIN ST
Any thoughts on how this can be done? I'm trying to avoid doing the first one then looking up the duplicates with a second query in the code.
First, use the GROUP BY clause to group all rows by the target column, which is the column that you want to check duplicate. Then, use the COUNT() function in the HAVING clause to check if any group have more than 1 element. These groups are duplicate.
MySQL is a database application that stores data in tables in the form of rows and columns. This database application can store duplicate records in the table, which can impact the performance of the database in MySQL.
One way to find duplicate records from the table is the GROUP BY statement. The GROUP BY statement in SQL is used to arrange identical data into groups with the help of some functions. i.e if a particular column has the same values in different rows then it will arrange these rows in a group.
SELECT date FROM logs group by date having count(*) >= 2
The key is to rewrite this query so that it can be used as a subquery.
SELECT firstname, lastname, list.address FROM list INNER JOIN (SELECT address FROM list GROUP BY address HAVING COUNT(id) > 1) dup ON list.address = dup.address;
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