Find and kill a process in one line using bash and regex

Question

I often need to kill a process during programming.

The way I do it now is:

[~]$ ps aux | grep 'python csp_build.py' user    5124  1.0  0.3 214588 13852 pts/4    Sl+  11:19   0:00 python csp_build.py user    5373  0.0  0.0   8096   960 pts/6    S+   11:20   0:00 grep python csp_build.py [~]$ kill 5124 

How can I extract the process id automatically and kill it in the same line?

Like this:

[~]$ ps aux | grep 'python csp_build.py' | kill <regex that returns the pid> 

Answer 1

In bash, you should be able to do:

kill $(ps aux | grep '[p]ython csp_build.py' | awk '{print $2}') 

Details on its workings are as follows:

• The ps gives you the list of all the processes.
• The grep filters that based on your search string, [p] is a trick to stop you picking up the actual grep process itself.
• The awk just gives you the second field of each line, which is the PID.
• The $(x) construct means to execute x then take its output and put it on the command line. The output of that ps pipeline inside that construct above is the list of process IDs so you end up with a command like kill 1234 1122 7654.

Here's a transcript showing it in action:

pax> sleep 3600 & [1] 2225 pax> sleep 3600 & [2] 2226 pax> sleep 3600 & [3] 2227 pax> sleep 3600 & [4] 2228 pax> sleep 3600 & [5] 2229 pax> kill $(ps aux | grep '[s]leep' | awk '{print $2}') [5]+  Terminated              sleep 3600 [1]   Terminated              sleep 3600 [2]   Terminated              sleep 3600 [3]-  Terminated              sleep 3600 [4]+  Terminated              sleep 3600 

and you can see it terminating all the sleepers.

---

Explaining the grep '[p]ython csp_build.py' bit in a bit more detail:

When you do sleep 3600 & followed by ps -ef | grep sleep, you tend to get two processes with sleep in it, the sleep 3600 and the grep sleep (because they both have sleep in them, that's not rocket science).

However, ps -ef | grep '[s]leep' won't create a process with sleep in it, it instead creates grep '[s]leep' and here's the tricky bit: the grep doesn't find it because it's looking for the regular expression "any character from the character class [s] (which is s) followed by leep.

In other words, it's looking for sleep but the grep process is grep '[s]leep' which doesn't have sleep in it.

When I was shown this (by someone here on SO), I immediately started using it because

• it's one less process than adding | grep -v grep; and
• it's elegant and sneaky, a rare combination :-)