Logo Questions Linux Laravel Mysql Ubuntu Git Menu
 

Filtering complex object inside nested ng-repeat

I want to filter object inside nested ng-repeat.

HTML:

<div ng-controller="MyController">
<input type="text" ng-model="selectedCityId" />
<ul>
    <li ng-repeat="shop in shops">
      <p ng-repeat = "locations in shop.locations | filter:search" style="display: block">
          City id: {{ locations.city_id }}
          <span style="padding-left: 20px; display: block;" ng-repeat="detail in locations.details | filter:item">Pin code: {{detail.pin}}</span>
      </p>    
    </li>
</ul>

Controller:

var myApp = angular.module('myApp', []);

myApp.controller('MyController', function ($scope) {

    $scope.search = function (location) {

        if ($scope.selectedCityId === undefined || $scope.selectedCityId.length === 0) {
            return true;
        }

           if (location.city_id === parseInt($scope.selectedCityId)) {
               return true;
            }
    };

    $scope.item = function (detail) {

        if ($scope.selectedCityId === undefined || $scope.selectedCityId.length === 0) {
            return true;
        }
        if (detail.pin == parseInt($scope.selectedCityId)) {
            return true;
        }
    };

    $scope.shops =
    [
       {
          "category_id":2,
          "locations":[
             {
                "city_id":368,
                "details": [{
                    "pin": 627718,
                  "state": 'MH'
                }]
             }
          ]
       },
       {
          "name":"xxx",
          "category_id":1,
          "locations":[
             {
                "city_id":400,
                "region_id":4,
                "details": [{
                    "pin": 627009,
                  "state": 'MH'
                },{
                    "pin": 129818,
                    "state": 'QA'
                }]
             },
          ]
       },
    ];

});

Here's the fiddle:

http://jsfiddle.net/suCWn/210/

I want to use multiple filter inside ng-repeat.

Example: Whenever user enters the ID in the input box. The list should filter based on cityID or PinCode. if user enter '129818' it should show pin code result of 129818 along with its parent cityID Similarly, if a user enter 400, the list should filter and show cityID result with 400 along with its child pin code.

EDIT:

Update Code http://codepen.io/chiragshah_mb/pen/aZorMe?editors=1010]

like image 522
Chirag Avatar asked May 24 '16 13:05

Chirag


4 Answers

First, you must not filter locations with matching details. Use something like this in the search filter:

$scope.search = function (location) {
    var id = parseInt($scope.selectedCityId);
    return isNaN(id) || location.city_id === id || 
           location.details.some(function(d) { return d.pin === id });
};

To show details if filtered by cityID, you have to find the parent location and check if it was filtered.

$scope.item = function (detail) {
    var id = parseInt($scope.selectedCityId);
    return isNaN(id) || detail.pin === id || locationMatches(detail, id);
};

function locationMatches(detail, id) {
    var location = locationByDetail(detail);
    return location && location.city_id === id;
}

function locationByDetail(detail) {
    var shops = $scope.shops;
    for(var iS = 0, eS = shops.length; iS != eS; iS++) {
      for(var iL = 0, eL = shops[iS].locations.length; iL != eL; iL++) {
        if (shops[iS].locations[iL].details.indexOf(detail) >= 0) {
          return shops[iS].locations[iL];
        }
      }
    }
}

EDIT Another, more flexible solution would be to remove all the filters from ngRepeats and do the filtering in a method that you call on ngChange of the search text. Here is the basic structure for this approach.

myApp.controller('MyController', function($scope, $http) { 
  var defaultMenu = [];
  $scope.currentMenu = [];
  $scope.searchText = '';

  $http.get(/*...*/).then(function (menu) { defaultMenu = menu; } );

  $scope.onSearch = function() {
    if (!$scope.searchText) {
      $scope.currentMenu = defaultMenu  ;
    }
    else {
      // do your special filter logic here...
    }
  };
});

And the template:

<input type="text" ng-model="searchText" ng-change="onSearch()" />
<ul>
    <li ng-repeat="category in currentMenu">
      ...   
    </li>
</ul>
like image 83
hansmaad Avatar answered Nov 17 '22 09:11

hansmaad


I have updated your filters. The problem is in your search filter you are only checking for the city_id, what you should do is:

  1. Check if the typed id is city_id
  2. Check if typed id is a pid of a child detail of given location

Similar thing for the item filter:

  1. Check if the typed id is a pid of the detail being filtered
  2. Check if the typed id is a city_id of the parent location of the detail passed in

Here is a working jsFiddle. I hope this helps.

like image 45
Daniel Gruszczyk Avatar answered Nov 17 '22 09:11

Daniel Gruszczyk


By simply modifying the JSON to include the city_id for children so you don't need to loop through it to get the parent's city_id, the solution is as easy as this:

var myApp = angular.module('myApp', []);
myApp.controller('MyController', function ($scope) {
    $scope.search = function (location) {
        if (!$scope.selectedCityId)
            return true;
        //if user's input is contained within a city's id
        if (location.city_id.toString().indexOf($scope.selectedCityId) > -1)
            return true;
        for (var i = 0; i < location.details.length; i++)
            //if user's input is contained within a city's pin
            if (location.details[i].pin.toString().indexOf($scope.selectedCityId) > -1)
                return true;
    };

    $scope.item = function (detail) {
        if (!$scope.selectedCityId)
            return true;
        //if user's input is contained within a city's id
        if (detail.city_id.toString().indexOf($scope.selectedCityId) > -1)
            return true;
        //if user's input is contained within a city's pin
        if (detail.pin.toString().indexOf($scope.selectedCityId) > -1)
            return true;
    };

Modified JSON

$scope.shops=[{"category_id":2,"locations":[{"city_id":368,"details":[{"city_id":368,"pin":627718,"state":'MH'}]}]},{"name":"xxx","category_id":1,"locations":[{"city_id":400,"region_id":4,"details":[{"city_id":400,"pin":627009,"state":'MH'},{"city_id":400,"pin":129818,"state":'QA'}]},]},];});

If directly modifying the JSON is not possible, you can modify it like this in this controller directly after this $scope.shops = ...json... statement:

for(var i=0; i<$scope.shops.length; i++)
    for(var j=0, cat=$scope.shops[i]; j<cat.locations.length; j++)
        for(var k=0, loc=cat.locations[j]; k<loc.details.length; k++)
            loc.details[k].city_id=loc.city_id;

Working fiddle: http://jsfiddle.net/87e314a0/

like image 1
Thalaivar Avatar answered Nov 17 '22 09:11

Thalaivar


I tried to make the solution easier to understand :

index.html :

<div ng-controller="MyController">
    <input type="text" ng-model="search.city_id" />
    <ul>
        <li ng-repeat="shop in shops">
          <p ng-repeat = "locations in shop.locations | filter:search.city_id" style="display: block">
              City id: {{ locations.city_id }}
              <span style="padding-left: 20px; display: block;" ng-repeat="detail in locations.details | filter:item">Pin code: {{detail.pin}}</span>
          </p>    
        </li>
    </ul>
</div>

app.js :

var myApp = angular.module('myApp', []);

myApp.controller('MyController', function ($scope) {
    $scope.shops =
[
   {
      "category_id":2,
      "locations":[
         {
            "city_id":368,
            "details": [{
                "pin": 627718,
              "state": 'MH'
            }]
         }
      ]
   },
   {
      "name":"xxx",
      "category_id":1,
      "locations":[
         {
            "city_id":400,
            "region_id":4,
            "details": [{
                "pin": 627009,
              "state": 'MH'
            },{
                "pin": 129818,
                            "state": 'QA'
            }]
         },
      ]
   },
];


});

Here's the fiddle : mySolution

like image 1
Nouâmane Raji Avatar answered Nov 17 '22 10:11

Nouâmane Raji