filtering a 3D numpy array according to 2D numpy array

Question

I have a 2D numpy array with the shape (3024, 4032).

I have a 3D numpy array with the shape (3024, 4032, 3).

2D numpy array is filled with 0s and 1s.

3D numpy array is filled with values between 0 and 255.

By looking at the 2D array values, I want to change the values in 3D array. If a value in 2D array is 0, I will change the all 3 pixel values in 3D array into 0 along the last axes. If a value in 2D array is 1, I won't change it.

I have checked this question, How to filter a numpy array with another array's values, but it applies for 2 arrays which have same dimensions. In my case, dimensions are different.

How the filtering is applied in two arrays, with same size on 2 dimensions, but not size on the last dimension?

Answer 1

Ok, I'll answer this to highlight one pecularity regarding "missing" dimensions. Lets' assume a.shape==(5,4,3) and b.shape==(5,4)

When indexing, existing dimensions are left aligned which is why @Divakar's solution a[b == 0] = 0 works.

When broadcasting, existing dimensions are right aligned which is why @InvaderZim's a*b does not work. What you need to do is a*b[..., None] which inserts a broadcastable dimension at the right