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Filling the gaps in D3 array nesting

Tags:

d3.js

nest

I have an array or objects consisting of a date and some values:

var flatData = [
    { "date": "2012-05-26", "product": "apple"  },
    { "date": "2012-07-03", "product": "orange" },
    ...
]

I am trying to use d3.nest() to get a count of these objects by year and then by month.

var nestedData = d3.nest()
    .key(function(d) { return d.date.split('-')[0]; })  // key is the year
    .sortKeys(d3.ascending)
    .key(function(d) {
        var splitDate = d.date.split('-');
        return splitDate[0] + '-' + splitDate[1]; // key is year-month
    })
    .sortKeys(d3.ascending)
    .rollup(function(d) {
        return d.length;
    })
    .entries(flatData);

This almost works, except that when there are no objects for a month, the nested data does not contain a record indicating a count of 0 for that month. Is there any trick to tell D3 to fill in these gaps?

(Of course, I can always do it the tedious way, i.e. to loop through all the nested levels and create a new data structure that fills in the gaps.)

like image 370
Naresh Avatar asked Jul 01 '13 23:07

Naresh


1 Answers

Try adding the missing data points after reduction:

var flatData = [
    { "date": "2012-05-26", "product": "apple"  },
    { "date": "2012-07-03", "product": "orange" }]

nestedData = d3.nest()
    .key(function(d) { return d.date.split('-')[0]; })  // key is the year
    .sortKeys(d3.ascending)
    .key(function(d) {
        var splitDate = d.date.split('-');
        return splitDate[0] + '-' + splitDate[1]; // key is year-month
    })
    .sortKeys(d3.ascending)
    .rollup(function(d) {
        return d.length;
    })
    .entries(flatData);


yMFormat = d3.time.format('%Y-%m')

makeAllKeys = function(year) {
    allKeys = [];
    for(var i = 0; i<12;i++) {  // 12 months in a year
        allKeys.push(yMFormat(new Date(year,i,1)));
    }
    return allKeys;
}

nestedData = nestedData.map(function(yearObj) {
    return {
        values: makeAllKeys(+yearObj.key).map(function(k) { 
                value = yearObj.values.filter(function(v) { return v.key == k; })[0];
                return value || ({key: k, values: 0});
            })
    };
});
like image 65
homam Avatar answered Oct 20 '22 01:10

homam