I want to fill a matrix from an array of indices :
import numpy as np
indx = [[0,1,2],[1,2,4],[0,1,3],[2,3,4],[0,3,4]]
x = np.zeros((5,5))
for i in range(5):
x[i,indx[i]] = 1.
The result is :
array([[ 1., 1., 1., 0., 0.],
[ 0., 1., 1., 0., 1.],
[ 1., 1., 0., 1., 0.],
[ 0., 0., 1., 1., 1.],
[ 1., 0., 0., 1., 1.]])
As desired.
Is there a way to do this in pure python/numpy without looping ?
Use advanced-indexing
after intialization -
x[np.arange(len(indx))[:,None], indx] = 1
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