This command fetches all tags:
git fetch origin --tags
This command fetches a specific tag:
git fetch origin refs/tags/1.0.0
But that doesn't let me do:
git checkout tags/2.3.18
How can I fetch a single tag and then perform a checkout?
Conclusion. You can download an individual file from a GitHub repository from the web interface, by using a URL, or from the command line. You can only retrieve public files by URL or from the command line.
If you have a single remote repository, then you can omit all arguments. just need to run git fetch , which will retrieve all branches and updates, and after that, run git checkout <branch> which will create a local copy of the branch because all branches are already loaded in your system.
git clone If you only need the specific tag, you can pass the --single-branch flag, which prevents fetching all the branches in the cloned repository. With the --single-branch flag, only the branch/tag specified by the --branch option is cloned. $ git clone -b <tagname> –single-branch <repository> .
git fetch --tags fetches all tags, all commits necessary for them. It will not update branch heads, even if they are reachable from the tags which were fetched.
git fetch origin refs/tags/1.0.0
This fails because it doesn't write a local reference: it obtains the remote's refs/tags/1.0.0
, and any tag object(s), commits, etc., required to go with it; it drops those into FETCH_HEAD
(as all git fetch
commands always do); and ... that's it. It never creates reference refs/tags/1.0.0
in your repository, even though it got everything it needed to do so.
To make it create such a tag if it does not yet exist:
git fetch origin refs/tags/1.0.0:refs/tags/1.0.0
The name on the right of the colon is the name your Git will use in your repository. You could turn this tag into a branch named wacky
, for instance, by naming it refs/heads/wacky
. (There's no reason to do this. I am describing this just for illustration.)
This is a non-forced fetch, so if you already have a refs/tags/1.0.0
, your Git will refuse to update your reference. If you wish to overwrite any existing 1.0.0
tag, use:
git fetch origin +refs/tags/1.0.0:refs/tags/1.0.0
If you wish to fetch all tags, with or without overwriting:
git fetch origin 'refs/tags/*:refs/tags/*'
with or without a leading plus sign. (Note: the quote marks are just to protect the *
from your shell. The plus sign may go inside or outside the quotes. In fact, the quotes themselves can go anywhere as long as they surround all asterisks or other shell meta-characters:
refs/tags/'*:refs/tags/*'
or you can use backslashes instead:
refs/tags/\*:refs/tags/\*
In all cases we are just protecting the sensitive asterisk from the shell's "asterisks are tasty, let's eat them" functions.)
I read all the answers, but there is not yet mentioned one syntactic sugar. If you need to fetch only one tag as a tag (to checkout later) you can write, for instance for refs/tags/2.3.18
:
git fetch origin tag 2.3.18 --no-tags
This is shortcut for already mentioned:
git fetch origin refs/tags/2.3.18:refs/tags/2.3.18 --no-tags
Of course, you may not use --no-tags
if you need other tags (according to the default behavior) or if you already explicitly set --no-tag
in the clone
command or in tagOpt
config option(man git-clone
).
git fetch origin tag 2.3.18
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