fclose(): Argument #1 ($stream) must be of type resource, bool given

Question

I just restart my laravel 8.0 project and I got this below error, please what could be wrong, this happens anytime I run "PHP artisan serve"

   TypeError

  fclose(): Argument #1 ($stream) must be of type resource, bool given

  at C:\Users\owner\Laravel-App\test-app\vendor\symfony\process\Pipes\WindowsPip
es.php:74
     70▕                         fclose($this->lockHandles[$pipe]);
     71▕                     }
     72▕                     $this->lockHandles[$pipe] = $h;
     73▕
  ➜  74▕                     if (!fclose(fopen($file, 'w')) || !$h = fopen($file
, 'r')) {
     75▕                         flock($this->lockHandles[$pipe], \LOCK_UN);
     76▕                         fclose($this->lockHandles[$pipe]);
     77▕                         unset($this->lockHandles[$pipe]);
     78▕                         continue 2;
       continue 2;

  1   C:\Users\owner\Laravel-App\test-app\vendor\symfony\process\Pipes\WindowsPi
pes.php:74
      fclose()

  2   C:\Users\owner\Laravel-App\test-app\vendor\symfony\process\Process.php:130
4
      Symfony\Component\Process\Pipes\WindowsPipes::__construct()

Answer 1

You can open the task manager then look for CLI (with the php logo) background process, if you find it then kill task

Answer 2

I had a Laravel application running that I forgot about (in the terminal of another IDE). Ctl + C (killing) that allowed me to get past this error msg.

Answer 3

Don't restart, don't uninstall, don't panic !

If you are on Windows Machine then follow these below step :

1. Click the Start charm.

2. Type cmd, right-click the Command Prompt tile, and then click Run as administrator.

3. Type tasklist /v | find "php" press enter and find the PID of php.exe

4. Kill the process by taskkill /PID <PID> /F

5. You are done.