Fatal error: Uncaught exception 'mysqli_sql_exception' with message 'No index used in query/prepared statement'

Question

When I run the following code, I get the error saying

Fatal error: Uncaught exception 'mysqli_sql_exception' with message 'No index used in query/prepared statement'

$mysql = new mysqli(DB_SERVER, DB_USER, DB_PASSWORD, DB_NAME) or die('There was a problem connecting to the database');
        if (mysqli_connect_errno()) {
            printf("DB error: %s", mysqli_connect_error());
            exit();
        }

    $get_emp_list = $mysql->prepare("SELECT id, name FROM calc");
    if(!$get_emp_list){
        echo "prepare failed\n";
        echo "error: ", $mysql->error, "\n";
        return;
    }
    $get_emp_list->execute();
    $get_emp_list->bind_result($id, $emp_list);

And this is the able schema --

--
-- Table structure for table `calc`
--

CREATE TABLE IF NOT EXISTS `calc` (
  `id` int(12) NOT NULL,
  `yr` year(4) NOT NULL,
  `mnth` varchar(12) NOT NULL,
  `name` varchar(256) NOT NULL,
  `paidleave` int(12) NOT NULL,
  `balanceleave` int(12) NOT NULL,
  `unpaidleave` int(12) NOT NULL,
  `basesalary` int(12) NOT NULL,
  `deductions` int(12) NOT NULL,
  `tds` int(12) NOT NULL,
  `pf` int(12) NOT NULL,
  `finalsalary` int(12) NOT NULL,
  PRIMARY KEY (`id`)
) ENGINE=MyISAM DEFAULT CHARSET=latin1;

Answer 1

The fatal error is not in MySQL; the missing index notification is a relatively low-severity warning.

The fatal error is in your PHP code, because of the following three conditions:

• mysqli reports a lot of warnings, even for relatively harmless conditions.
• You're throwing mysqli_sql_exception for all errors and warnings due to your mysqli_report(MYSQLI_REPORT_ALL); line.
• Your PHP code is not catching that exception (i.e. it's not in a try{} block with an appropriate catch(){} block), and uncaught exceptions are fatal.

You can't do much about the first one, as mentioned in the other answer. So, you can fix it either by changing your mysqli_report(...) setting to MYSQLI_REPORT_STRICT or MYSQLI_REPORT_OFF, or indeed anything other than MYSQLI_REPORT_ALL.

(edit: w3d's comment below gives a good explanation why, and suggests you could use mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT) as a good alternative)

For best practices, and in combination with this, you should fix it properly by using try{} and catch(){} appropriately within your code.