Menu
What is the fastest way to detect if a vector has at least 1 NA in R? I've been using:
sum( is.na( data ) ) > 0 But that requires examining each element, coercion, and the sum function.
567
To test if a value is NA, use is.na(). The function is.na(x) returns a logical vector of the same size as x with value TRUE if and only if the corresponding element in x is NA.
To identify missing values use is.na() which returns a logical vector with TRUE in the element locations that contain missing values represented by NA .
We can remove those NA values from the vector by using is.na(). is.na() is used to get the na values based on the vector index. ! is.na() will get the values except na.
%in% operator can be used in R Programming Language, to check for the presence of an element inside a vector. It returns a boolean output, evaluating to TRUE if the element is present, else returns false.
I'm thinking:
any(is.na(data)) should be slightly faster.
191
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With
