{"A":100,
"B":[{"Title":"Age","Match":false},{"Title":"Height","Match":false},{"Title":"Country","Match":false},{"Title":"Gender","Match":false},{"Title":"Language","Match":True}],
"C":78}
I have a table in SQL Server database and one column (columnName) has JSON text. I would like to extract values and return result in separate columns.
I tried:
SELECT JSON_VALUE(columnName, $.A) AS Score, -- This works --
JSON_VALUE(columnName, $.B.Title...) AS Age, -- How can I access the Age, Match values --
JSON_VALUE(columnName, $.C) AS FinalScore -- This works --
I think for A and C it worked because they have one value but B has list of objects.
You need a statement like the following. You should parse the input JSON with OPENJSON() and explicit schema (columns definitions):
Table:
CREATE TABLE Data (JsonData varchar(1000))
INSERT INTO Data (JsonData)
VALUES ('{"A":100,
"B":[{"Title":"Age","Match":false},{"Title":"Height","Match":false},{"Title":"Country","Match":false},{"Title":"Gender","Match":false},{"Title":"Language","Match":true}],
"C":78}')
Statement:
SELECT j1.A, j1.C, j2.*
FROM Data d
CROSS APPLY OPENJSON (d.JsonData) WITH (
A int '$.A',
B nvarchar(max) '$.B' AS JSON,
C int '$.C'
) j1
CROSS APPLY OPENJSON (j1.B) WITH (
Title varchar(500) '$.Title',
Match bit '$.Match'
) j2
Result:
A C Title Match
100 78 Age False
100 78 Height False
100 78 Country False
100 78 Gender False
100 78 Language True
Note, that the reason for the NULL results is the fact, that B key in the input JSON is a JSON array, so you need to use JSON_QUERY() to get the whole JSON array and additional CROSS APPLY to parse this array. JSON_VALUE() extracts a scalar value from a JSON string and if the path points to not a scalar value, the result is NULL in lax mode and an error in strict mode.
SELECT
JSON_VALUE(d.JsonData, '$.A') AS A,
JSON_QUERY(d.JsonData, '$.B') AS B,
JSON_VALUE(d.JsonData, '$.C') AS C,
j.*
FROM Data d
CROSS APPLY OPENJSON(d.JsonData, '$.B') WITH (
Title varchar(500) '$.Title',
Match bit '$.Match'
) j
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