extracting a string between two quotes in bash

Question

I have example string like Test "checkin_resumestorevisit - Online_V2.mt" Run

and i want to extract the text between the two quotes in bash. I tried using command like

SUBSTRING=${echo $SUBSTRING| cut -d'"' -f 1 }

but it fails with error: bad substitution.

Answer 1

If you want to extract content between the first " and the last ":

s='Test "checkin_resumestorevisit - Online_V2.mt" Run'
s=${s#*'"'}; s=${s%'"'*}
echo "$s"

Answer 2

In order to extract the substring between quotes you can use one of these alternatives:

Alternative 1:

SUBSTRING=`echo "$SUBSTRING" | cut -d'"' -f 2`

Alternative 2:

SUBSTRING=`echo "$SUBSTRING" | awk -F'"' '{print $2}'`

Alternative 3:

set -f;IFS='"'; SUBSTRING=($SUBSTRING); SUBSTRING=${SUBSTRING[1]};set +f