I have started using the JSON data type in mysql 5.7. Is there a way to extract a value without the quotation marks? For instance when setting up a virtual index.
Example:
mysql> INSERT INTO test (data) VALUES ('{"type": "user" ,
"content" : { "username": "jdoe", "firstname" : "John", "lastname" : "Doe" } }');
mysql> SELECT json_extract(data,'$.type') FROM test;
+-----------------------------+
| json_extract(data,'$.type') |
+-----------------------------+
| "user" |
+-----------------------------+
How to get
+-----------------------------+
| json_extract(data,'$.type') |
+-----------------------------+
| user |
+-----------------------------+
?
We can use the JSON_EXTRACT function to extract data from a JSON field. The basic syntax is: JSON_EXTRACT(json_doc, path) For a JSON array, the path is specified with $[index] , where the index starts from 0: mysql> SELECT JSON_EXTRACT('[10, 20, 30, 40]', '$[0]'); +------------------------------------------+
In MySQL, the JSON_UNQUOTE() function “unquotes” a JSON document and returns the result as a utf8mb4 string. You provide the JSON document as an argument, and the function will do the rest.
JSON_EXTRACT. Extracts a JSON value, such as an array or object, or a JSON scalar value, such as a string, number, or boolean. JSON-formatted STRING or JSON. JSON_EXTRACT_SCALAR. Extracts a scalar value.
Two aggregate functions generating JSON values are available. JSON_ARRAYAGG() returns a result set as a single JSON array, and JSON_OBJECTAGG() returns a result set as a single JSON object.
You can use ->>
operator to extract unquoted data, simply!
SELECT JSONCOL->>'$.PATH' FROM tableName
Two other ways:
JSON_UNQUOTE(JSON_EXTRACT(column, path))
JSON_UNQUOTE(column->path)
Note: Three different ways yield to the same command, as EXPLAIN
explains:
As with ->, the ->> operator is always expanded in the output of EXPLAIN, as the following example demonstrates:
EXPLAIN SELECT c->>'$.name' AS name FROM jemp WHERE g > 2 ; SHOW WARNINGS ; *************************** 1. row *************************** Level: Note Code: 1003 Message: /* select#1 */ select json_unquote(json_extract(`jtest`.`jemp`.`c`,'$.name')) AS `name` from `jtest`.`jemp` where (`jtest`.`jemp`.`g` > 2) 1 row in set (0.00 sec)
read more on MySQL Reference Manual https://dev.mysql.com/doc/refman/5.7/en/json-search-functions.html#operator_json-inline-path
Note: The ->>
operator was added in MySQL 5.7.13
You can use JSON_UNQUOTE() method:
SELECT JSON_UNQUOTE(json_extract(data,'$.type')) FROM test;
This method will deal with internal quotes, for instance:
SET @t1 := '{"a": "Hello \\\"Name\\\""}';
SET @j := CAST(@t1 AS JSON);
SET @tOut := JSON_EXTRACT(@j, '$.a');
SELECT @t1, @j, @tOut, JSON_UNQUOTE(@tOut), TRIM(BOTH '"' FROM @tOut);
will give:
@t1 : {"a": "Hello \"Name\""}
@j : {"a": "Hello \"Name\""}
@tOut : "Hello \"Name\""
unquote : Hello "Name"
trim : Hello \"Name\
I believe that the unquote is better in almost all circumstances.
MySQL 8.0.21 supports JSON_VALUE
function
Extracts a value from a JSON document at the path given in the specified document, and returns the extracted value, optionally converting it to a desired type. The complete syntax is shown here:
JSON_VALUE(json_doc, path [RETURNING type] [on_empty] [on_error]) on_empty: {NULL | ERROR | DEFAULT value} ON EMPTY on_error: {NULL | ERROR | DEFAULT value} ON ERROR
If not specified by a RETURNING clause, the JSON_VALUE() function's return type is VARCHAR(512)
db<>fiddle demo
SELECT json_value(data,'$.type')
FROM test;
-- user
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