I go through this part:
How do I extract the data from that URL? I only want to print out the "networkdiff": 58954.60268219
.
from urllib import urlopen
url = urlopen('http://21.luckyminers.com/index.php?page=api&action=getpoolstatus&api_key=8dba7050f9fea1e6a554bbcf4c3de5096795b253b45525c53562b72938771c41').read()
print url
This is what the API display as a result from print url command:
{
"getpoolstatus": {
"version": "1.0.0",
"runtime": 16.618967056274,
"data": {
"pool_name": "21 Coin Pool @ Luckyminers.com",
"hashrate": 485426748,
"efficiency": 98.1,
"workers": 14,
"currentnetworkblock": 12025,
"nextnetworkblock": 12026,
"lastblock": 12023,
"networkdiff": 58954.60268219,
"esttime": 521.61956775542,
"estshares": 241478052.58625,
"timesincelast": 427,
"nethashrate": 485426748
}
}
}
You can use the json
module to parse out a Python dictionary and get right to the value like so:
import json
result = json.loads(url) # result is now a dict
print '"networkdiff":', result['getpoolstatus']['data']['networkdiff']
To do this multiple times (to answer your question in the comments section):
import json
import urllib
urls = {'joe': 'url1', 'jack': 'url2', 'jane': 'url3'}
for who in urls.keys():
url = urllib.urlopen(urls[who])
result = json.loads(url) # result is now a dict
print 'For %s: "networkdiff":' % who, result['getpoolstatus']['data']['networkdiff']
convert the response to json and then read it
from urllib import urlopen
import simplejson as json
url = urlopen('http://21.luckyminers.com/index.php?page=api&action=getpoolstatus&api_key=8dba7050f9fea1e6a554bbcf4c3de5096795b253b45525c53562b72938771c41').read()
url = json.loads(url)
print url.get('getpoolstatus').get('data').get('networkdiff')
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