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extension of Dictionary where <String, AnyObject>

I am trying to create a dictionary extension where Dictionary is of the type <String, AnyObject>.

Was looking in many places and trying different approaches, but none of them seemed to work. This was one of them:

extension Dictionary where <String, AnyObject>{
    var jsonString:String {
        return ""
    }
}

Another method that didn't actually work for some reason:

extension Dictionary where Key:Hashable, Value:AnyObject {

    var jsonString:String {

        do {
           let stringData = try NSJSONSerialization.dataWithJSONObject(self, options: NSJSONWritingOptions.PrettyPrinted)
            if let string = String(data: stringData, encoding: NSUTF8StringEncoding){
                return string
            }
        }catch _ {

        }
        return ""
    }
}

Got: Argument type 'Dictionary' does not conform to expected type of 'AnyObject'

like image 255
Andrius Steponavičius Avatar asked Sep 16 '15 13:09

Andrius Steponavičius


4 Answers

>=3.1

From 3.1, we can do concrete extensions, ie:

extension Dictionary where Key == String {}

<3.1

We can not conform concrete types w/ concrete generics, ie:

extension Dictionary where Key == String

However, because Dictionary conforms to sequence and we can conform protocol types w/ concrete generics, we could do:

extension Sequence where Iterator.Element == (key: String, value: AnyObject) {
    func doStuff() {...

Otherwise, we can constrain our key to a protocol that string conforms to like this:

extension Dictionary where Key: StringLiteralConvertible, Value: AnyObject {
    var jsonString: String {
        return ""
    }
}

As per your updated answer. Json serialization needs an object, Swift Dictionaries are structs. You need to convert to an NSDictionary You must specify Key to conform to NSObject to properly convert to an NSDictionary.

Small note: Dictionaries already type constrain Key to be Hashable, so your original constraint wasn't adding anything.

extension Dictionary where Key: NSObject, Value:AnyObject {

    var jsonString:String {

        do {
            let stringData = try NSJSONSerialization.dataWithJSONObject(self as NSDictionary, options: NSJSONWritingOptions.PrettyPrinted)
            if let string = String(data: stringData, encoding: NSUTF8StringEncoding){
                return string
            }
        }catch _ {

        }
        return ""
    }
}

Note, that the dictionaries must conform to this type to access the extension.

let dict = ["k" : "v"]

Will become type [String : String], so you must be explicit in declaring:

let dict: [NSObject : AnyObject] = ["k" : "v"]
like image 143
Logan Avatar answered Nov 16 '22 05:11

Logan


Swift 3 Approach

extension Dictionary where Key: ExpressibleByStringLiteral, Value: AnyObject

As StringLiteralConvertible is now deprecated and replaced by ExpressibleByStringLiteral

like image 41
Aidan Malone Avatar answered Nov 16 '22 04:11

Aidan Malone


Update for Swift 3
Here is my example using ExpressibleByStringLiteral for Key and Any for Value.

extension Dictionary where Key: StringLiteralConvertible, Value: Any {
    var jsonString: String? {
        if let dict = (self as AnyObject) as? Dictionary<String, AnyObject> {
            do {
                let data = try JSONSerialization.data(withJSONObject: dict, options: JSONSerialization.WritingOptions(rawValue: UInt.allZeros))
                if let string = String(data: data, encoding: String.Encoding.utf8) {
                    return string
                }
            } catch {
                print(error)
            }
        }
        return nil
    }
}

and then I use it like this:

let dict: Dictionary<String, AnyObject> = [...]
let jsonString = dict.jsonString

You can convert self to AnyObject or NSObject, both works, then you do unwrap as Dictionary or any other specific type.

like image 31
Jonauz Avatar answered Nov 16 '22 05:11

Jonauz


Adding to the answer provided by @Logan, for those looking to add custom properties to the string-subscripted Dictionary, that is possible as well (was looking to do this when I came across this SO question):

extension Dictionary where Key: StringLiteralConvertible {

    var somePropertyThatIsAColor:UIColor? {
        get {
            return self["someKey"] as? UIColor
        }
        set {
            // Have to cast as optional Value
            self["someKey"] = (newValue as? Value)
    }

}
like image 29
Jason Henderson Avatar answered Nov 16 '22 03:11

Jason Henderson