Express.JS get url path without any additional parameters

Question

Is there any straightforward way to get URL path segment without any additional data (url parameters, css '#', etc.)

for example:

full URL: http://example.com/panel/list
path segment I want to get: /panel/list

full URL: http://example.com/panel/list?user=joe
path segment I want to get: /panel/list

full URL: http://example.com/panel/list#header
path segment I want to get: /panel/list

And any other combination of data that is not path segment of my URL

Answer 1

I think you can use req.baseUrl + req.path.

And for full URL use req.originalUrl.