exit with error message in bash (oneline)

Question

Is it possible to exit on error, with a message, without using if statements?

[[ $TRESHOLD =~ ^[0-9]+$ ]] || exit ERRCODE "Threshold must be an integer value!" 

Of course the right side of || won't work, just to give you better idea of what I am trying to accomplish.

Actually, I don't even mind with which ERR code it's gonna exit, just to show the message.

EDIT

I know this will work, but how to suppress numeric arg required showing after my custom message?

[[ $TRESHOLD =~ ^[0-9]+$ ]] || exit "Threshold must be an integer value!" 

Answer 1

exit doesn't take more than one argument. To print any message like you want, you can use echo and then exit.

    [[ $TRESHOLD =~ ^[0-9]+$ ]] || \      { echo "Threshold must be an integer value!"; exit $ERRCODE; } 

Answer 2

You can use a helper function:

function fail {     printf '%s\n' "$1" >&2 ## Send message to stderr.     exit "${2-1}" ## Return a code specified by $2, or 1 by default. }  [[ $TRESHOLD =~ ^[0-9]+$ ]] || fail "Threshold must be an integer value!" 

Function name can be different.