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Is it possible to execute a process whose argc = 0? I need to execute a program but it is extremely important for its argc to be equal to 0. Is there a way to do that? I tried to put 2^32 arguments in the command line so that it appears as if argc = 0 but there is a maximum limit to the number of arguments.
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Yes, it can be zero, meaning that argv[0] == NULL . It's a convention that argv[0] is the name of the program. You can have argc == 0 if you launch yourself the binary, like with execve family and don't give any argument.
By convention, argv[0] is the command with which the program is invoked. argv[1] is the first command-line argument. The last argument from the command line is argv[argc - 1] , and argv[argc] is always NULL.
argc is the count of arguments, and argv is an array of the strings. The program itself is the first argument, argv[0] , so argc is always at least 1.
You can write a program that calls exec directly; that allows you to specify the command-line arguments (including the program name) and lack thereof.
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