Execute multiple commands in a bash script sequentially and fail if at least one of them fails

Question

I have a bash script that I use to execute multiple commands in sequence and I need to return non-zero exit code if at least one command in the sequence returns non-zero exit code. I know there is a wait command for that but I'm not sure I understand how to use it.

UPD The script looks like this:

#!/bin/bash command1 command2 command3 

All the commands run in foreground. All the commands need to run regardless of which exit status the previous command returned (so it must not behave as "exit on first error"). Basically I need to gather all the exit statuses and return global exit status accordingly.

Answer 1

Just do it:

EXIT_STATUS=0 command1 || EXIT_STATUS=$? command2 || EXIT_STATUS=$? command3 || EXIT_STATUS=$? exit $EXIT_STATUS 

Not sure which of the statuses it should return if several of commands have failed.