Could somebody please provide the code to do the following: Assume there is a directory of files, all of which need to be run through a program. The program outputs the results to standard out. I need a script that will go into a directory, execute the command on each file, and concat the output into one big output file.
For instance, to run the command on 1 file:
$ cmd [option] [filename] > results.out
We can run all scripts in a directory or path using "run-parts" command. The run-parts command is used to run scripts or programs in a directory or path. One disadvantage with run-parts command is it won't execute all scripts. It will work only if your scripts have the correct names.
The semicolon (;) operator allows you to execute multiple commands in succession, regardless of whether each previous command succeeds. For example, open a Terminal window (Ctrl+Alt+T in Ubuntu and Linux Mint). Then, type the following three commands on one line, separated by semicolons, and press Enter.
The following bash code will pass $file to command where $file will represent every file in /dir
for file in /dir/* do cmd [option] "$file" >> results.out done
Example
el@defiant ~/foo $ touch foo.txt bar.txt baz.txt el@defiant ~/foo $ for i in *.txt; do echo "hello $i"; done hello bar.txt hello baz.txt hello foo.txt
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