Following code gives a compilation error (at least when using MS VS 2008) for line "e=f" in main():
error C2582: 'operator =' function is unavailable in 'B'
class A {
public:
A() { }
static const double x;
};
const double A::x = 0.0;
class B {
public:
B() : x(0.0) { }
const double x;
};
int main( int argc, char *argv[] )
{
A c,d;
B e,f;
c = d;
e = f;
return 0;
}
The default assignment operator should be generated for both classes, A and B !?
in 12.8.10: "If the class definition does not explicitly declare a copy assignment operator, one is declared implicitly."
The implicitly generated operator would recursively assign each non-static member. However, x
is const
, so it can't be assigned to. This prevents the implicit operator from being generated (specifically, it causes it to be defined as deleted).
This is specified in C++11 12.8/23:
A defaulted copy/move assignment operator for class X is defined as deleted if X has:
- ...
- a non-static data member of const non-class type (or array thereof), or
- ...
(Although I just noticed that your compiler predates C++11; the rules are similar, but specified in different language, in older dialects with no concept of "deleted" functions).
If you want an assignment operator for a class whose members (or base classes) can't be reassigned, you'll have to define it yourself.
In class A
, the constant member is static, so doesn't form part of an object. Therefore, it doesn't prevent an (empty) object from being assigned to.
field 'x'
is of const-qualified type of const double
, the default assignment operator will be meaningless and is implicitly deleted here
The obvious difference between class A and B is const member x beeing static vs. non-static. Assignment to a const variable is/should be impossible in any case.
The compiler obviously tries to generate the default assignment operator method for class B and silently decides to not generating one, as member x does not allow assignment.
Took me quite a long time to find out this ...
BTW: If you omit the initialization of x in class B , compiler is smart enough to find out this mistake.
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