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Here are four paths:
p1=r'\foo\bar\foobar.txt' p2=r'\foo\bar\foo\foo\foobar.txt' p3=r'\foo\bar\foo\foo2\foobar.txt' p4=r'\foo2\bar\foo\foo\foobar.txt' The directories may or may not exist on a drive. What would be the most elegant way to create the directories in each path?
I was thinking about using os.path.split() in a loop, and checking for a dir with os.path.exists, but I don't know it there's a better approach.
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Example 1: Using pathlib.mkdir to create a nested directory. Import class Path from pathlib library. Call the module mkdir() with two arguments parents and exist_ok . By default, parents is set False .
The exist_ok parameter (Python 3.2 or later) If exist_ok=True , you can specify an existing directory without error. Note that the default is exist_ok=False . In older versions without exist_ok , you can use try to handle exceptions, or use os.
Python method makedirs() is recursive directory creation function. Like mkdir(), but makes all intermediate-level directories needed to contain the leaf directory.
You are looking for os.makedirs() which does exactly what you need.
The documentation states:
Recursive directory creation function. Like mkdir(), but makes all intermediate-level directories needed to contain the leaf directory. Raises an error exception if the leaf directory already exists or cannot be created.
Because it fails if the leaf directory already exists you'll want to test for existence before calling os.makedirs().
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On Python 3.6+ you can do:
import pathlib path = pathlib.Path(p4) path.parent.mkdir(parents=True, exist_ok=True) If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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