Elastic Search - exclude index and type from json response

Question

When I execute a query over an index like this:

{
   "_source":["bar"] , "size":100,
   "query": {
       "match_all": {}
   },
   "filter": {
       "type" : {
           "value" : "foo"
        }
    }
}

the response includes index, type, etc. But I already know the index and type because I specified it. This information just bloats up the size of the json data. Is there a way to exclude these from the response?

This is what I get:

{
"took": 31,
"timed_out": false,
"_shards": {
    "total": 5,
    "successful": 5,
    "failed": 0
    },
"hits": {
    "total": 364024,
    "max_score": 1,
    "hits": [
          {
        "_index": "foo_bar",
        "_type": "foo",
        "_id": "asdjj123123",
        "_score": 1,
        "_source": {
          "bar": "blablablabla"
    }
  }
,...

What I want is something like this, so a response without type,score,index:

{
"took": 31,
"timed_out": false,
"_shards": {
    "total": 5,
    "successful": 5,
    "failed": 0
    },
"hits": {
    "total": 364024,
    "max_score": 1,
    "hits": [
          {
        "_id": "asdjj123123",
        "_source": {
          "bar": "blablablabla"
    }
  }
,...

Answer 1

Yes, as of ES 1.6, you can use response filtering and using the filter_path parameter in the query enumerate only what you need in the response:

curl -XGET 'localhost:9200/foo_bar/foo/_search?pretty&filter_path=hits.total,hits.max_score,hits.hits._id,hits.hits._source'

Answer 2

_source option can be used to achieve this.

When you query a JSON and you don't want to use filter path, you can do as below

{
  "_source":{
     "includes":["field1", "field2"],
     "excludes":["_index", "_type", "_score"]
  }
}

You can define only includes, only excludes or Both. Response works accordingly.