Efficiently getting all divisors of a given number

Question

According to this post, we can get all divisors of a number through the following codes.

for (int i = 1; i <= num; ++i){     if (num % i == 0)         cout << i << endl; } 

For example, the divisors of number 24 are 1 2 3 4 6 8 12 24.

After searching some related posts, I did not find any good solutions. Is there any efficient way to accomplish this?

My solution:

1. Find all prime factors of the given number through this solution.
2. Get all possible combinations of those prime factors.

However, it doesn't seem to be a good one.

Answer 1

Factors are paired. 1 and 24, 2 and 12, 3 and 8, 4 and 6.

An improvement of your algorithm could be to iterate to the square root of num instead of all the way to num, and then calculate the paired factors using num / i.