efficient way to convert 16 bit value to 8 bit value

Question

I have a variable that holds 16-bit value. I need only 8 LSB. Rest 8 bits needs to be discarded.

I am using this code for doing this.

#include<stdio.h>
#include<stdint.h>
int main(int argc, char *argv[])
{
    int linkIndx,size=128;

    uint16_t val = 0xABCD;
    uint8_t vr;

    vr = val; //this assignment discards upper 8-bits 

    printf("0x%X 0x%X ", val, vr);
}

Result:

0xABCD 0xCD

I want to know, Is it a good way to take 8 LSB from 16 bit variable?

EDIT:
Please add performance issues (from memory and speed perspective) with this particular way of implementation.

Answer 1

You can do as below:

uint16_t val = 0xABCD;
uint8_t vr = val & 0x00FF;    // Bitwise AND Operation

Using this bitwise operation you will get 8 bits of LSB