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In a game I'm making, I've got two points, pt1 and pt2, and I want to work out the angle between them. I've already worked out the distance, in an earlier calculation. The obvious way would be to arctan the horizontal distance over the vertical distance (tan(theta) = opp/adj).
I'm wondering though, as I've already calculated the distance, would it be quicker to use arcsine/arccosine with the distance and dx or dy?
Also, might I be better off pre-calculating in a table?
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Most computer trig libraries are based on polynomial approximations, which gives the best balance between speed an accuracy. For example, a dozen or so multiplication and add/subtract operations is enough to give full single-precision accuracy for sine and cosine.
cos x ∈ [-1,1] Hence, for the trigonometric functions f(x)= sin x and f(x)= cos x, the domain will consist of the entire set of real numbers, as they are defined for all the real numbers. The range of f(x) = sin x and f(x)= cos x will lie from -1 to 1, including both -1 and +1, i.e.
Aside from all of the wise comments regarding premature optimization, let's just assume this is the hotspot and do a frigg'n benchmark:
Times are in nanoseconds, scaled to normalize 'acos' between the systems.
'acos' simply assumes unit radius i.e. acos(adj), whereas 'acos+div' means acos(adj/hyp).
System 1 is a 2.4GHz i5 running Mac OS X 10.6.4 (gcc 4.2.1)
System 2 is a 2.83GHz Core2 Quad running Red Hat 7 Linux 2.6.28 (gcc 4.1.2)
System 3 is a 1.66GHz Atom N280 running Ubuntu 10.04 2.6.32 (gcc 4.4.3)
System 4 is a 2.40GHz Pentium 4 running Ubuntu 10.04 2.6.32 (gcc 4.4.3)
Summary: Relative performance is all over the map. Sometimes atan2 is faster, sometimes its slower. Very strangely, on some systems doing acos with a division is faster than doing it without. Test on your own system :-/
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I suspect there's a risk of premature optimization here. Also, be careful about your geometry. Your opposite/adjacent approach is a property of right angle triangles, is that what you actually have?
I'm assuming your points are planar, and so for the general case you have them implicitly representing two vectors form the origin (call these v1 v2), so your angle is
theta=arccos(dot(v1,v2)/(|v1||v2|)) where |.| is vector length.
Making this faster (assuming the need) will depend on a lot of things. Do you know the vector lengths, or have to compute them? How fast can you do a dot product in your architecture. How fast is acos? At some point tricks like table lookup (probably interpolated) might help but that will cost you accuracy.
It's all trade-offs though, there really isn't a general answer to your question.
[edit: added commentary]
I'd like to re-emphasize that often playing "x is fastest" is a bit of a mugs game with modern cpus and compilers anyway. You won't know until you measure it and grovel the generated code. When you hit the point that you really care about it at this level for a (hopefully small) piece of code, you can find out in detail what your system is doing. But it's painstaking. Maybe a table is good. But maybe you've got fast vector computations and a small cache. etc. etc. etc. It all amounts to "it depends". Sorry 'bout that. On the other hand, if you haven't reached the point that you really care so much about this bit of code... you probably shouldn't be thinking about it at this level at all. Make it right. Make it clean (which means abstraction as well as code). Then worry about the overhead.
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