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Dojo and unregistering widgets

I am new to the Dojo Toolkit. I'm getting the error

Tried to register widget with id=myButton but that id is already registered 

whenever I try to load dojo content twice (meaning I load HTML content through jQuery.Load into a container div). Is there a way of unregistering already registered widgets in dojo? I've seen some examples, but I don't really get them working.

My button:

<button dojoType="dijit.form.Button" id="myButton">button</button> 
like image 895
John Korsnes Avatar asked May 04 '10 08:05

John Korsnes


2 Answers

If you're looking to unregister specific widgets, you can use their destroy() or destroyRecursive() methods. The second one destroys any widgets inside the one you are destroying (i.e. calling destroyRecursive on a form widget will also destroy all the form components).

In your case, it sounds like your best bet would be to do this before jQuery.load -

var widgets = dijit.findWidgets(<containerDiv>); dojo.forEach(widgets, function(w) {     w.destroyRecursive(true); }); 

The above code will unregister all widgets in <containerDiv>, and preserve their associated DOM Nodes. To destroy the DOM nodes, pass false to destroyRecursive instead.

Reference:

http://dojotoolkit.org/api/1.3/dijit/_Widget/destroyRecursive

like image 194
Jez Avatar answered Oct 22 '22 06:10

Jez


Based on http://bugs.dojotoolkit.org/ticket/5438, I found a sufficient way of destroying dojo-widgets:

dijit.registry.forEach(function(w){                   w.destroy();                        }); 
like image 35
John Korsnes Avatar answered Oct 22 '22 05:10

John Korsnes