Does the most efficient solution to some problems require mutable data?

Question

I've been dabbling in Haskell - so still very much a beginner.

I'm been thinking about the counting the frequency of items in a list. In languages with mutable data structures, this is typically solved using a hash table - a dict in Python or a HashMap in Java for example. The complexity of such a solution is O(n) - assuming the hash table can fit entirely in memory.

In Haskell, there seem to be two (mainstream) choices - to sort the data then group and count it or use a Data.Map. If a sort is used, it dominates the run-time of the solution, so the complexity is O(n log n). Likewise, Data.Map uses a balanced tree, so inserting n elements into it will also have complexity O(n log n).

If my analysis is correct, then I assume that this particular problem is most efficiently solved by resorting to a mutable data structure. Are there other types of problems where this is also true? How in general do people using Haskell approach something like this?

Answer 1

The question whether we can implement any algorithm with optimal complexity in a pure language is currently unknown. Nicholas Pippenger has proven that there is a problem that must necessarily have a log(n) penalty in a pure strict language compared to the optimal algorithm. However, there is a followup paper which shows that this problem have an optimal solution in a lazy language. So at the end of the day we really don't know. Though it seems that most people think that there is an inherent log(n) penalty for some problems, even for lazy languages.