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I make some research in order to look for the sscanf() source code . But I could not find the answer to my question.
when we use sscanf() in this way:
char str[50] = "5,10,15";
int x;
sscanf(str,"%d,%s",&x,str);
Does sscanf() support "recursive" buffer str ?
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This happens because every scanf() leaves a newline character in a buffer that is read by the next scanf. How to Solve the Above Problem? We can make scanf() to read a new line by using an extra \n, i.e., scanf(“%d\n”, &x) . In fact scanf(“%d “, &x) also works (Note the extra space).
You are correct: sscanf indeed does not "move", because there is nothing to move. If you need to scan a bunch of ints, you can use strtol - it tells you how much it read, so you can feed the next pointer back to the function on the next iteration.
scanf() It is used to read the input(character, string, numeric data) from the standard input(keyboard). It is used to read the input until it encounters a whitespace, newline or End Of File(EOF).
It doesn't break from self modifying buffer. But to make it (tail)recursive, you'd have to read to the end of the string.
The code fragment:
char str[]="5,10,15";
int a[10]={0},x = 0;
while (sscanf(str,"%d,%s",a+ x++,str)>1);
reads all the integers.
Since this is not really recursive and the string to be read doesn't overwrite the asciiz in the string, I believe this is "safe" in the meaning: only try this at home.
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