Does s take 3 bytes in Java? when : String s = "abc"; Java

Question

If I write this in Java:

String s = "abc";  

Does s only occupy 3 bytes in the memory?
If true, how JVM finds the end of the String object?
Does this take more bytes in memory?

Answer 1

It takes more than 3 bytes, read on for full explanation from this page

For reasons we'll explore below, the minimum memory usage of a Java String (in the Hotspot Java 6 VM) is generally as follows:

Minimum String memory usage (bytes) = 8 * (int) ((((no chars) * 2) + 45) / 8)

Or, put another way:

• multiply the number of characters of the String by two;
• add 38;
• if the result is not a multiple of 8, round up to the next multiple of 8;
• the result is generally the minimum number of bytes taken up on the heap by the String.

This page from the same website also details ways in which you can save memory using classes different than String