Menu
According to the Rust documentation:
Vectors always allocate their data on the heap.
As I understand this, it means that:
T in a contiguous fashion.In other words, if I add a few integers to a vector, while the Vec will allocate enough storage to store those integers, it's not also going to box those integers; introducing another layer of indirection.
I'm not sure how I can illustrate or confirm this with code examples but any help is appreciated.
662
Vector is a module in Rust that provides the container space to store values. It is a contiguous resizable array type, with heap-allocated contents. It is denoted by Vec<T>. Vectors in Rust have O(1) indexing and push and pop operations in vector also take O(1) complexity.
All values in Rust are stack allocated by default. Values can be boxed (allocated on the heap) by creating a Box<T> . A box is a smart pointer to a heap allocated value of type T . When a box goes out of scope, its destructor is called, the inner object is destroyed, and the memory on the heap is freed.
Because a Box<T> is a pointer, Rust always knows how much space a Box<T> needs: a pointer's size doesn't change based on the amount of data it's pointing to. This means we can put a Box<T> inside the Cons variant instead of another List value directly.
A contiguous growable array type, written as Vec<T> , short for 'vector'.
Yes, Vec<T> will store all items in a contiguous buffer rather than boxing them individually. The documentation states:
A contiguous growable array type, written
Vec<T>but pronounced 'vector.'
Note that it is also possible to slice a vector, to get a &[T] (slice). Its documentation, again, confirms this:
A dynamically-sized view into a contiguous sequence,
[T].Slices are a view into a block of memory represented as a pointer and a length.
136
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With
