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For example -
#include <memory> int main(){ const auto bufSize = 1024; auto buffer = std::make_unique<char[]>(bufSize); } Is the buffer here already filled with '\0' characters or will I have to manually fill it to avoid garbage values.
And what would be the possible way to do this, will std::memset(&buffer.get(), 0, bufSize) suffice?
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char ZEROARRAY[1024] = {0}; The compiler would fill the unwritten entries with zeros. Alternatively you could use memset to initialize the array at program startup: memset(ZEROARRAY, 0, 1024);
Using the 'make_unique' function to create the pointer helps solve this problem by guaranteeing the freeing of memory if an exception occurs. The C++17 standard, while still not specifying the exact evaluation order for arguments, provides additional guarantees.
All of the make_* functions use value-initialization for the type if you don't provide constructor parameters. Since the array-form of make_unique doesn't take any parameters, it will zero-out the elements.
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