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And, if it does, how do you use one? (syntax)
Also, why does or why doesn't C support lambda expressions?
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The anonymous function is not supported by standard C programming language, but supported by some C dialects, such as GCC and Clang.
With the new Lambda Runtime API, a new door of possibilities is open. This C++ runtime enables you to do more with Lambda than you ever could have before. More in-depth details, along with examples, can be found on the GitHub repository. With it, you can start writing Lambda functions with C++ today.
One of the new features introduced in Modern C++ starting from C++11 is Lambda Expression. It is a convenient way to define an anonymous function object or functor. It is convenient because we can define it locally where we want to call it or pass it to a function as an argument.
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No, C has no support for lambda expressions.
If you're willing to use C++, Boost has a library that emulates lambdas. Also, C++0x will have built-in support for lambda expressions.
There wasn't a huge demand for lambda expression support in C at the time, so the language didn't support it.
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C does not support lambda expressions, nor any other ways (within the language's standard) to dynamically create functions -- all functions, per the standard, are created at compile time. I guess the reason is to keep the language small, simple, lean, and very fast, with hardly any "runtime library" support necessary -- crucial for a language that's so widely used in programming operating systems, device drivers, embedded applications, and so forth.
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No, C doesn't have lambda expressions (or any other way to create closures).
This is likely so because C is a low-level language that avoids features that might have bad performance and/or make the language or run-time system more complex.
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