Django Template Filter Syntax error

Question

I am trying to use django's built in 'default' filter using this code

{% load sekizai_tags static compress i18n %} [...] <title>{{ title|default:"nothing" }}</title> 

But it gives me the following exception

django.template.base.TemplateSyntaxError: default requires 2 arguments, 1 provided 

I am using the following settings for my Template Backend

TEMPLATES = [     {         'BACKEND': 'django.template.backends.django.DjangoTemplates',         'DIRS': [             str(APPS_DIR.path('templates')),         ],         'OPTIONS': {             'debug': DEBUG,             'loaders': [                 'django.template.loaders.filesystem.Loader',                 'django.template.loaders.app_directories.Loader',             ],             'context_processors': [                 'django.template.context_processors.debug',                 'django.template.context_processors.request',                 'django.contrib.auth.context_processors.auth',                 'allauth.account.context_processors.account',                 'allauth.socialaccount.context_processors.socialaccount',                 'django.template.context_processors.i18n',                 'django.template.context_processors.media',                 'django.template.context_processors.static',                 'django.template.context_processors.tz',                 'django.contrib.messages.context_processors.messages',                 'sekizai.context_processors.sekizai',             ],         },     }, ] 

My editor marks the code as invalid, but i check like a thousand of times https://docs.djangoproject.com/en/1.8/ref/templates/builtins/

Where this is given as example:

{{ value|default:"nothing" }} 

I also tried to change the name of title var, to make sure it is not a reserved keyword.

Answer 1

Make sure you don't have a space after the colon.

This is correct:

{{ title|default:"nothing" }} 

This throws an exception:

{{ title|default: "nothing" }}