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So, I am new to Django, and cannot for the life of me figure out why I keep getting a TypeError on my view.
Error is:
TypeError at /
filename must be a string, not None
Request Method: GET
Request URL: http://127.0.0.1:8000/
Django Version: 1.8.5
Exception Type: TypeError
Exception enter code hereValue:
filename must be a string, not None
I have the following in the view
<!DOCTYPE html>
{% load sass_tags %}
<html>
<head lang="en">
...
<link href="{% sass_src 'app_name/static/theme.scss' %}" media="screen" rel="stylesheet" type="text/css">
I am probably missing something in my settings.py, but not sure what it could be. Also, how do I link to my scss file?
I added the following in my settings.py
INSTALLED_APPS = [
....
'sass_processor',
....
]
STATICFILES_FINDERS = (
'sass_processor.finders.CssFinder',
)
I think my problem lies here
SASS_PROCESSOR_INCLUDE_DIRS = (
os.path.join(BASE_DIR, 'app_name/static'),
)
BASE_DIR refers to
BASE_DIR = os.path.dirname(os.path.dirname(os.path.abspath(__file__)))
Where exactly should this point to? my app structure is
app_dir/
Specs/
src/
app_name/
static/
theme.scss
templates/
__init__.py
views.py
etc...
I thought its a Python3 error, so I buillt a 2.7 ve, but still have the exact same issue.
784
I realized this went unanswered, but I did find the problem thanks to jrief
This needs to be in the settings file
INSTALLED_APPS = [
....
'sass_processor',
....
]
....
....
STATIC_ROOT = os.path.join(BASE_DIR, 'app_name/static/')
STATIC_URL = '/static/'
The link in the html
<link href="{% sass_src 'filename.scss' %}" rel="stylesheet" type="text/css"/>
These weren't required
SASS_PROCESSOR_INCLUDE_DIRS = (
os.path.join(BASE_DIR, 'app_name/static'),
)
STATICFILES_FINDERS = (
'sass_processor.finders.CssFinder',
)
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