Django object not saving even after "save" call

Question

I'm really at a loss because this makes no sense at all. I call save/create an object, and it dosn't show up in the admin site. I even checked the SQLite database with a SQLite Viewer program, which again showed that the item had not been saved.

This is the code that saves the Data object:

        data = Data(represents=field, for_entry=entry, value="This can be anything")
        # field is a DataField db object and entry is a Entry db object (see model below and paragraph)
        print("B4", data) #<---- Shows that Data has not been assigned an ID/pk
        data.save()
        print("8ER: ", data) #<--- Shows that Data has been assigned an ID/pk

As you can see from my comments, I know that the Data object is assigned an ID after the save call, which I would think meant that it worked. No error is thrown anywhere. field, and entry are all both. Each one seems to be ok, as in they have the right IDs, were retrieved with [table name].objects.get(id=...), and I can save/edit them and their saves change.

Even strange, this exact code in a function that is called right before this one works.

This is my model.py (I took out some functions to make it shorter):

class Entry(models.Model):
    parent = models.ForeignKey('Entry', blank = True, null = True, default=None) #  The entry this subs. Is left blank for top level entries.
    id_number = models.CharField(max_length=20)
    visible = models.BooleanField()
    data_field = models.ForeignKey('DataField', default=1)  # The field that this entire entry falls under. REDUNDANT BUT NECISSARY

    def __str__(self):
        return str(self.id)+ "-" + str(self.id_number) 

class DataField(models.Model):
    parent = models.ForeignKey('DataField', related_name='parent field', null=True, blank=True, default=1)
    order = models.IntegerField()
    multiple_entries = models.BooleanField(default=True)
    DATA_TYPES = (('t', 'Text'), ('d', 'Date'), ('l', 'List'), ('o', 'Option'), ('b', 'Boolean'), ('f', 'Foreign Key'), ('r', 'Root'), ('bb', 'Branch'), ('i', 'Image'), ('ff', 'File'), ('h', 'Holder'), ('bt', 'Big Text'))  # A number means it is a foreign key. Should go off title.
    foreign_source = models.ForeignKey('DataField', null=True, blank=True) #  Points to DATA FIELD WHO'S MATCHING DATA WILL MAKE UP THE OPTIONS
    data_type = models.CharField(max_length=2, choices=DATA_TYPES, default='t', null=True, blank=True)
    title = models.CharField(max_length=100, null=True, blank=True)
    visibility = models.BooleanField(default=False)

    def __str__(self):
        return str(self.id) + "-" + str(self.title)

    def __eq__(self, other):
        if not isinstance(other, DataField):
            return False
        if self.data_type == 'h':
            return self.title == other.title
        return self.id == other.id


class Data(models.Model):
    represents = models.ForeignKey('DataField')
    for_entry = models.ForeignKey('Entry', null=True)
    value = models.CharField(max_length=1000000)

    def __str__(self):
        return self.represents.title + "-" + str(self.for_entry.id) + "-" + str(self.value) + "-" + str(self.id)

It's possible that I'm missing something obvious, or maybe you need way more information than I can provide to fix it. If there is not enough information, please comment and request more info, or just list possible issues that could be happening.

Answer 1

I had the same issue. I solved it by assigned the object to a new variable, making my changes and saving the new variable:

    location = self.location  # self.location is set by other methods
    location.is_active = True
    location.save()

Answer 2

Try a manual commit. I don't know what else to suggest.

from django.db import transaction

@transaction.commit_manually
def viewfunc(request):
    ...
    data.save()
    transaction.commit()