I have a website where users can see a list of movies, and create reviews for them.
The user should be able to see the list of all the movies. Additionally, IF they have reviewed the movie, they should be able to see the score that they gave it. If not, the movie is just displayed without the score.
They do not care at all about the scores provided by other users.
Consider the following models.py
from django.contrib.auth.models import User from django.db import models class Topic(models.Model): name = models.TextField() def __str__(self): return self.name class Record(models.Model): user = models.ForeignKey(User) topic = models.ForeignKey(Topic) value = models.TextField() class Meta: unique_together = ("user", "topic")
What I essentially want is this
select * from bar_topic left join (select topic_id as tid, value from bar_record where user_id = 1) on tid = bar_topic.id
Consider the following test.py
for context:
from django.test import TestCase from bar.models import * from django.db.models import Q class TestSuite(TestCase): def setUp(self): t1 = Topic.objects.create(name="A") t2 = Topic.objects.create(name="B") t3 = Topic.objects.create(name="C") # 2 for Johnny johnny = User.objects.create(username="Johnny") johnny.record_set.create(topic=t1, value=1) johnny.record_set.create(topic=t3, value=3) # 3 for Mary mary = User.objects.create(username="Mary") mary.record_set.create(topic=t1, value=4) mary.record_set.create(topic=t2, value=5) mary.record_set.create(topic=t3, value=6) def test_raw(self): print('\nraw\n---') with self.assertNumQueries(1): topics = Topic.objects.raw(''' select * from bar_topic left join (select topic_id as tid, value from bar_record where user_id = 1) on tid = bar_topic.id ''') for topic in topics: print(topic, topic.value) def test_orm(self): print('\norm\n---') with self.assertNumQueries(1): topics = Topic.objects.filter(Q(record__user_id=1)).values_list('name', 'record__value') for topic in topics: print(*topic)
BOTH tests should print the exact same output, however, only the raw version spits out the correct table of results:
raw --- A 1 B None C 3
the orm instead returns this
orm --- A 1 C 3
Any attempt to join back the rest of the topics, those that have no reviews from user "johnny", result in the following:
orm --- A 1 A 4 B 5 C 3 C 6
How can I accomplish the simple behavior of the raw query with the Django ORM?
edit: This sort of works but seems very poor:
topics = Topic.objects.filter(record__user_id=1).values_list('name', 'record__value') noned = Topic.objects.exclude(record__user_id=1).values_list('name') for topic in chain(topics, noned): ...
edit: This works a little bit better, but still bad:
topics = Topic.objects.filter(record__user_id=1).annotate(value=F('record__value')) topics |= Topic.objects.exclude(pk__in=topics)
orm --- A 1 B 5 C 3
Left outer join includes the unmatched rows from the table which is on the left of the join clause whereas a Right outer join includes the unmatched rows from the table which is on the right of the join clause.
Join can be done with select_related method: Django defines this function as Returns a QuerySet that will “follow” foreign-key relationships, selecting additional related-object data when it executes its query.
Django gives you two ways of performing raw SQL queries: you can use Manager. raw() to perform raw queries and return model instances, or you can avoid the model layer entirely and execute custom SQL directly. Explore the ORM before using raw SQL!
First of all, there is no a way (atm Django 1.9.7) to have a representation with Django's ORM of the raw query you posted, exactly as you want; however, you can get the same desired result with something like:
>>> Topic.objects.annotate( f=Case( When( record__user=johnny, then=F('record__value') ), output_field=IntegerField() ) ).order_by( 'id', 'name', 'f' ).distinct( 'id', 'name' ).values_list( 'name', 'f' ) >>> [(u'A', 1), (u'B', None), (u'C', 3)] >>> Topic.objects.annotate(f=Case(When(record__user=may, then=F('record__value')), output_field=IntegerField())).order_by('id', 'name', 'f').distinct('id', 'name').values_list('name', 'f') >>> [(u'A', 4), (u'B', 5), (u'C', 6)]
Here the SQL generated for the first query:
>>> print Topic.objects.annotate(f=Case(When(record__user=johnny, then=F('record__value')), output_field=IntegerField())).order_by('id', 'name', 'f').distinct('id', 'name').values_list('name', 'f').query >>> SELECT DISTINCT ON ("payments_topic"."id", "payments_topic"."name") "payments_topic"."name", CASE WHEN "payments_record"."user_id" = 1 THEN "payments_record"."value" ELSE NULL END AS "f" FROM "payments_topic" LEFT OUTER JOIN "payments_record" ON ("payments_topic"."id" = "payments_record"."topic_id") ORDER BY "payments_topic"."id" ASC, "payments_topic"."name" ASC, "f" ASC
##Some notes
distinct
with positional arguments is used in this answer, which is available for PostgreSQL only, atm. In the docs you can see more about conditional expressions.If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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