Newbie question: I need to accept a parameter in a form from a method in views.py but it gave me troubles. In the view I created a method with following snippet:
def scan_page(request):
myClient = request.user.get_profile().client
form = WirelessScanForm(client = myClient) # pass parameter to the form
and in the forms.py I defined the following form:
class WirelessScanForm(forms.ModelForm):
time = forms.DateTimeField(label="Schedule Time", widget=AdminSplitDateTime())
def __init__(self,*args,**kwargs):
myClient = kwargs.pop("client") # client is the parameter passed from views.py
super(WirelessScanForm, self).__init__(*args,**kwargs)
prob = forms.ChoiceField(label="Sniffer", choices=[ x.sniffer.plug_ip for x in Sniffer.objects.filter(client = myClient) ])
But django keeps giving me error saying: TemplateSyntaxError: Caught NameError while rendering: name 'myClient' is not defined
(This error happens in the query)
I'm afraid it would be something stupid missing here, but I cannot really figure out why. Please help, thanks.
Assuming I've corrected your formatting properly, you have an indentation issue: prob
is outside __init__
, so doesn't have access to the local myClient
variable.
However if you bring it inside the method, it still won't work, as there are two other issues: first, simply assigning a field to a variable won't set it on the form; and second, the choices
attribute needs a list of 2-tuples, not just a flat list. What you need is this:
def __init__(self,*args,**kwargs):
myClient = kwargs.pop("client") # client is the parameter passed from views.py
super(WirelessScanForm, self).__init__(*args,**kwargs)
self.fields['prob'] = forms.ChoiceField(label="Sniffer", choices=[(x.plug_ip, x.MY_DESCRIPTIVE_FIELD) for x in Sniffer.objects.filter(client = myClient)])
Obviously replace MY_DESCRIPTIVE_FIELD
with the actual field you want displayed in the choices.
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