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Django : Filter query based on custom function

I've got a function built into my Django model class and I want to use that function to filter my query results.

  class service:        ......        def is_active(self):             if datetime.now() > self.end_time:                   return False             return True 

Now I want to use this function into my query filter, something like

nserv = service.objects.filter(is_active=True) 

I know, for this simple 'is_active' case, I can directly make this comparision in filter query, but for more complex situations, that may not be possible. How should I make a query, based on custom functions?

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Neo Avatar asked Apr 16 '11 07:04

Neo


2 Answers

I just had a similar issue. The problem was i had to return a QuerySet instance. A quick solution for me was to do something like this:

active_serv_ids = [service.id for service in Service.objects.all() if service.is_active()] nserv = Service.objects.filter(id__in=active_serv_ids) 

I'm pretty sure this is not the prettiest and performant way to do this, but it works for me.

A more verbose way of doing this would be:

active_serv_ids = []  for service in Service.objects.all():     if service.is_active():         active_serv_ids.append(service.id)  nserv = Service.objects.filter(id__in=active_serv_ids) 
like image 51
Walter Renner Avatar answered Sep 19 '22 21:09

Walter Renner


I would suggest you to use a custom manager for your class, like this you could use :

nserv = service.objects.are_active()

This would be achieved with something like:

class ServiceManager(models.Manager):     def are_active(self):         # use your method to filter results         return you_custom_queryset 

See custom managers

like image 37
Lapin-Blanc Avatar answered Sep 19 '22 21:09

Lapin-Blanc