Change a string of integers separated by spaces to a list of int

Question

How do i make something like

x = '1 2 3 45 87 65 6 8'  >>> foo(x) [1,2,3,45,87,65,6,8] 

I'm completely stuck, if i do it by index, then the numbers with more than 1 digit will be broken down. Help please.

Answer 1

The most simple solution is to use .split()to create a list of strings:

x = x.split() 

Alternatively, you can use a list comprehension in combination with the .split() method:

x = [int(i) for i in x.split()] 

You could even use map map as a third option:

x = list(map(int, x.split())) 

This will create a list of int's if you want integers.