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Django Error Reporting - How to know which user triggered the error?

Is there a way I can customize Django error reporting so when it emails me it lets me know which user triggered the error?

I'm in Django 1.2 if it matters.

Much Thanks in advance!

like image 707
Greg Avatar asked Jul 13 '11 12:07

Greg


2 Answers

If you don't want to use sentry you can use this simple middleware to attache the user-infos to the error mail:

# source: https://gist.github.com/646372
class ExceptionUserInfoMiddleware(object):
    """
    Adds user details to request context on receiving an exception, so that they show up in the error emails.

    Add to settings.MIDDLEWARE_CLASSES and keep it outermost(i.e. on top if possible). This allows
    it to catch exceptions in other middlewares as well.
    """

    def process_exception(self, request, exception):
        """
        Process the exception.

        :Parameters:
           - `request`: request that caused the exception
           - `exception`: actual exception being raised
        """

        try:
            if request.user.is_authenticated():
                request.META['USERNAME'] = str(request.user.username)
                request.META['USER_EMAIL'] = str(request.user.email)
        except:
            pass

You can simply put this class in a *.py file anywhere below your Django project and add a reference to MIDDLEWARE_CLASSES. I.e. if you put it in a file "middleware" in the project root (where your settings.py is) , you simply add middleware.ExceptionUserInfoMiddleware.

like image 85
Martin Thurau Avatar answered Oct 16 '22 13:10

Martin Thurau


I highly recommend http://readthedocs.org/docs/sentry/en/latest/index.html for the job.

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iElectric Avatar answered Oct 16 '22 13:10

iElectric