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Disambiguate template specialization between map-like and vector-like containers

template<class> struct Printer;

// I want this to match std::vector (and similar linear containers) 
template<template<class, class...> class T, class TV, class... TS> 
    struct Printer<T<TV, TS...>> { ... };

// I want this to match std::map (and similar map-like containers)
template<template<class, class, class...> class TM, class TK, class TV, typename... TS> 
    struct Printer<TM<TK, TV, TS...>> { ... }

int main() 
{
    // Both of these match the second specialization, which is only intended
    // for std::map (and similar map-like containers)
    Printer<std::vector<int>>::something();
    Printer<std::map<int, float>>::something();
}

As you can see from the example, std::vector and std::map both match the second specialization. I think it's because std::vector's allocator parameter gets matched to TV, which is intended for std::map's value.

How can I match std::vector (and other linear containers) with the first specialization and std::map (and other key-value containers) with the second one?

like image 435
Vittorio Romeo Avatar asked Feb 09 '14 14:02

Vittorio Romeo


1 Answers

The problem with the pattern-matching approach is that it will only ever work if for every single container you write a specialization. This is tedious work.

Instead you can rely on other properties:

  • a container will necessarily be iterable over via begin(c) and end(c) expressions
  • on top of this, an associative container will have a ::key_type nested type, among others, as expressed in § 23.2.4 [associative.rqmts].

Therefore, we can whip up a classifier, based on tag dispatching:

inline constexpr auto is_container_impl(...) -> std::false_type {
    return std::false_type{};
}

template <typename C>
constexpr auto is_container_impl(C const* c) ->
    decltype(begin(*c), end(*c), std::true_type{})
{
    return std::true_type{};
}

template <typename C>
constexpr auto is_container(C const& c) -> decltype(is_container_impl(&c)) {
    return is_container_impl(&c);
}

inline constexpr auto is_associative_container_impl(...)
    -> std::false_type
{ return std::false_type{}; }

template <typename C, typename = typename C::key_type>
constexpr auto is_associative_container_impl(C const*) -> std::true_type {
    return std::true_type{};
}

template <typename C>
constexpr auto is_associative_container(C const& c)
    -> decltype(is_associative_container_impl(&c))
{
    return is_associative_container_impl(&c);
}

And now you can write "simple" code:

template <typename C>
void print_container(C const& c, std::false_type/*is_associative*/) {
}

template <typename C>
void print_container(C const& c, std::true_type/*is_associative*/) {
}

template <typename C>
void print_container(C const& c) {
    return print_container(C, is_assocative_container(c));
}

Now, this might not be exactly what you wish for, because under this requirements a set is an associative container, but its value is not a pair, so you cannot print key: value. You have to adapt the tag-dispatching to your needs.

like image 89
Matthieu M. Avatar answered Oct 05 '22 23:10

Matthieu M.