Disabling sorting mechanism in pprint output

Question

I have big dictionary which I`m printing for viewing with prettyprint, but how I can keep formatting but kill sorting mechanism in pprint?

Answer 1

Python 3.8 or newer:

Use sort_dicts=False:

pprint.pprint(data, sort_dicts=False) 

Python 3.7 or older:

You can monkey patch the pprint module.

import pprint  pprint.pprint({"def":2,"ghi":3,"abc":1,}) pprint._sorted = lambda x:x # Or, for Python 3.7: # pprint.sorted = lambda x, key=None: x pprint.pprint({"def":2,"ghi":3, "abc":1}) 

Since the 2nd output is essentiallly randomly sorted, your output may be different from mine:

{'abc': 1, 'def': 2, 'ghi': 3} {'abc': 1, 'ghi': 3, 'def': 2} 

---

Another version that is more complex, but easier to use:

import pprint import contextlib  @contextlib.contextmanager def pprint_nosort():     # Note: the pprint implementation changed somewhere     # between 2.7.12 and 3.7.0. This is the danger of     # monkeypatching!     try:         # Old pprint         orig,pprint._sorted = pprint._sorted, lambda x:x     except AttributeError:         # New pprint         import builtins         orig,pprint.sorted = None, lambda x, key=None:x      try:         yield     finally:         if orig:             pprint._sorted = orig         else:             del pprint.sorted  # For times when you don't want sorted output with pprint_nosort():     pprint.pprint({"def":2,"ghi":3, "abc":1})  # For times when you do want sorted output pprint.pprint({"def":2,"ghi":3, "abc":1}) 

Answer 2

As of Python 3.8, you can finally disable this using sort_dicts=False. Note that dictionaries are insertion-ordered since Python 3.7 (and in practice, even since 3.6).

import pprint  data = {'not': 'sorted', 'awesome': 'dict', 'z': 3, 'y': 2, 'x': 1} pprint.pprint(data, sort_dicts=False) # prints {'not': 'sorted', 'awesome': 'dict', 'z': 3, 'y': 2, 'x': 1} 

Alternatively, create a pretty printer object:

pp = pprint.PrettyPrinter(sort_dicts=False) pp.pprint(data) 

This does not affect sets (which are still sorted), but then sets do not have insertion-ordering guarantees.