Difference between string object and string literal [duplicate]

Question

When you use a string literal the string can be interned, but when you use new String("...") you get a new string object.

In this example both string literals refer the same object:

String a = "abc"; 
String b = "abc";
System.out.println(a == b);  // true

Here, 2 different objects are created and they have different references:

String c = new String("abc");
String d = new String("abc");
System.out.println(c == d);  // false

In general, you should use the string literal notation when possible. It is easier to read and it gives the compiler a chance to optimize your code.

A String literal is a Java language concept. This is a String literal:

"a String literal"

A String object is an individual instance of the java.lang.String class.

String s1 = "abcde";
String s2 = new String("abcde");
String s3 = "abcde";

All are valid, but have a slight difference. s1 will refer to an interned String object. This means, that the character sequence "abcde" will be stored at a central place, and whenever the same literal "abcde" is used again, the JVM will not create a new String object but use the reference of the cached String.

s2 is guranteed to be a new String object, so in this case we have:

s1 == s2 // is false
s1 == s3 // is true
s1.equals(s2) // is true

The long answer is available here, so I'll give you the short one.

When you do this:

String str = "abc";

You are calling the intern() method on String. This method references an internal pool of String objects. If the String you called intern() on already resides in the pool, then a reference to that String is assigned to str. If not, then the new String is placed in the pool, and a reference to it is then assigned to str.

Given the following code:

String str = "abc";
String str2 = "abc";
boolean identity = str == str2;

When you check for object identity by doing == (you are literally asking: do these two references point to the same object?), you get true.

However, you don't need to intern() Strings. You can force the creation on a new Object on the Heap by doing this:

String str = new String("abc");
String str2 = new String("abc");
boolean identity = str == str2;

In this instance, str and str2 are references to different Objects, neither of which have been interned, so that when you test for Object identity using ==, you will get false.

In terms of good coding practice: do not use == to check for String equality, use .equals() instead.

As Strings are immutable, when you do:

String a = "xyz"

while creating the string, the JVM searches in the pool of strings if there already exists a string value "xyz", if so 'a' will simply be a reference of that string and no new String object is created.

But if you say:

String a = new String("xyz")

you force JVM to create a new String reference, even if "xyz" is in its pool.

For more information read this.