I have this awk
statement:
glb_library="my_library"
awk "
/^Direct Dependers of/ { next }
/^---/ { next }
/^$glb_library:/ { ver=\$0; next }
{ gsub(/[[:space:]]/, '', \$0); print ver':'\$0 }
" file
Basically, I have enclosed the awk
code in double quotes so that the shell variable glb_library
is expanded. I have made sure to escape the $
character to prevent the shell from expanding $0
. Followed the guidance from here.
awk
gives me this error:
awk: syntax error at source line 5
context is
{ gsub(/[[:space:]]/, >>> ' <<<
I want to understand:
awk
? Why is ''
not a null string like ""
is?awk
treat single and double quotes differently?My code worked after I escaped the single quotes with backslashes and used \"\"
to represent the null string instead of ''
.
Never enclose any script in double quotes or you're sentencing yourself to backslash-hell. This is the syntax for what you're trying to do:
glb_library="my_library"
awk -v glb_library="$glb_library" '
/^Direct Dependers of/ { next }
/^---/ { next }
$0 ~ "^"glb_library":" { ver=$0; next }
{ gsub(/[[:space:]]/, ""); print ver":"$0 }
' file
Based on the comments above by awk experts and some research, I am posting this answer:
Further clarification:
""
is the null string in awk, not ''
"Ed's answers are great!"
other techniques followed while handling single quotes in awk are:
a) use a variable, as in awk -v q="'" '{ print q }' ...
b) use octal or hex notation, as in awk '{ print "\047"$0"\047" }' ...
Relevant documentation here.
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