What is the difference between boost::ref(i)
and & i
? What are the situations where we cannot use regular references and have to go for boost::ref
instead? Please include examples if possible.
From the Boost.Ref Documentation:
The purpose of boost::reference_wrapper is to contain a reference to an object of type T. It is primarily used to "feed" references to function templates (algorithms) that take their parameter by value.
NB: An important difference between boost::reference_wrapper
and std::reference_wrapper
(at least of Boost 1.52) is the ability of std::reference_wrapper
to perfectly wrap function objects.
This enables code like this:
// functor that counts how often it was applied
struct counting_plus {
counting_plus() : applications(0) {}
int applications;
int operator()(const int& x, const int& y)
{ ++applications; return x + y; }
};
std::vector<int> x = {1, 2, 3}, y = {1, 2, 3}, result;
counting_plus f;
std::transform(begin(x), end(x), begin(y),
std::back_inserter(result), std::ref(f));
std::cout << "counting_plus has been applied " << f.applications
<< " times." << '\n';
In Boost.Thread for example :
A new thread is launched by passing an object of a callable type that can be invoked with no parameters to the constructor. The object is then copied into internal storage, and invoked on the newly-created thread of execution. If the object must not (or cannot) be copied, then boost::ref can be used to pass in a reference to the function object. In this case, the user of Boost.Thread must ensure that the referred-to object outlives the newly-created thread of execution.
Code from doc :
struct callable
{
void operator()();
};
boost::thread copies_are_safe()
{
callable x;
return boost::thread(x);
} // x is destroyed, but the newly-created thread has a copy, so this is OK
boost::thread oops()
{
callable x;
return boost::thread(boost::ref(x));
} // x is destroyed, but the newly-created thread still has a reference
// this leads to undefined behaviour
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